4cos^2x-sin^2(2x)+5sin^2x=4

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Solution for 4cos^2x-sin^2(2x)+5sin^2x=4 equation: 


Simplifying
4cos2x + -1sin2(2x) + 5sin2x = 4

Remove parenthesis around (2x)
4cos2x + -1in2s * 2x + 5sin2x = 4

Reorder the terms for easier multiplication:
4cos2x + -1 * 2in2s * x + 5sin2x = 4

Multiply -1 * 2
4cos2x + -2in2s * x + 5sin2x = 4

Multiply in2s * x
4cos2x + -2in2sx + 5sin2x = 4

Combine like terms: -2in2sx + 5in2sx = 3in2sx
4cos2x + 3in2sx = 4

Solving
4cos2x + 3in2sx = 4

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3in2sx' to each side of the equation.
4cos2x + 3in2sx + -3in2sx = 4 + -3in2sx

Combine like terms: 3in2sx + -3in2sx = 0
4cos2x + 0 = 4 + -3in2sx
4cos2x = 4 + -3in2sx

Divide each side by '4os2x'.
c = o-1s-2x-1 + -0.75in2o-1s-1

Simplifying
c = o-1s-2x-1 + -0.75in2o-1s-1

Reorder the terms:
c = -0.75in2o-1s-1 + o-1s-2x-1

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